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sin x z Cos y z

求微分,有 cos(x+z)*(dx+dz) = -sin(y+z)*(dy+dz), 整理成 dz = ----dx+----dy, 两个偏导数就出来了。

d(xyz)=-sin(x+y+z)d(x+y+z) yzdx+xzdy+xydz=-sin(x+y+z)(dx+dy+dz) (xy+sin(x+y+z))dz=(-yz-sin(x+y+z))dx+(-xz-sin(x+y+z))dy dz=(-yz-sin(x+y+z))/(xy+sin(x+y+z))dx+(-xz-sin(x+y+z))/(xy+sin(x+y+z))dy 所以 az/ax=(-yz-sin(x+y+z))/(xy+si...

sin(x+z)=cos(y+z) 两边对x求偏导: cos(x+z)·(1+∂z/∂x)=-sin(y+z)·∂z/∂x→∂z/∂x=-cos(x+z)/[sin(y+z)+cos(x+z)] 两边对x求偏导: cos(x+z)·∂z/∂y=-sin(y+z)·(1+∂z/∂y)→∂z/&#...

clear all[x,y] = meshgrid(0:.01*pi:2*pi);z = sin(x/2).*cos(y);mesh(x,y,z)

x=linspace(-5,5,50); y=linspace(-5,5,50); [x,y]=meshgrid(x,y); z=sin(x).*sin(y); figure(1) meshc(x,y,z); figure(2) [C, h] = contourf(z); clabel(C, h, 'LabelSpacing', 72); colorbar; tm1 = colormap(hot(9)); tm1(1, :) = [1 1 1]; c...

>> t=0:0.05*pi:10*pi;>> x=sin(t);y=cos(t);z=t;>> plot3(x,y,z)>> xlabel('sin(t)'); ylabel('cos(t)'); zlabel('z');>> grid on

把 z=[y1 y2] 改成 z=[y1; y2]。 因为y1、y2都是行向量,拼接成矩阵时应该放在不同行里。

z=xcos(x^2-y) dz=cos(x^2-y)dx+x[-sin(x^2-y)]*(2xdx-ydy) =cos(x^2-y)dx-2x^2sin(x^2-y)dx+xysin(x^2-y)dy =[cos(x^2-y)-2x^2sin(x^2-y)]dx+xysin(x^2-y)dy 则: z对x的偏导数为:cos(x^2-y)-2x^2sin(x^2-y) z对y的偏导数为:xysin(x^2-y)

个人观点,可能有误:1·这应该是螺旋线的参数方程,即表明,在三维坐标中,一点在沿某一方向高度增加的同时,它到处于这个方向上的直线的距离符合某个函数。即若选z轴为该点高度增加的方向,则x^2+y^2=f(x)。 2.在研究关于不同轴旋转时,各研究...

标准球坐标 x²+y²+(z-a)² = a² x²+y²+z² = 2az x = r sinφ cosθ y = r sinφ sinθ z = r cosφ dV = r²sinφ drdφdθ Ω方程变为:r = 2acosφ 由于整个球面在xOy面上,所以0 ≤ φ ≤ π/2 ∫_(Ω) (x²+y...

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